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If then value of is
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Correct option is B
Note that 0≤3r≤15⇒0≤r≤5. Also, 15!(14−r)!(r+1)!×(3r)!(15−3r)!15!=311⇒ (3r)!(15−3r)!(14−r)!(r+1)!=311 1For the denominator, to be divisible by 11,11∣(14−r)!Setting 14−r=11. ⇒ r=3Putting r = 3, in LHS of (1) we getLHS of (1) 9!6!11!4!=6×511×10=311= = RHS of (1) ∴ r=3Similar Questions
is equal to
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