If $$Cr=nCr$$,then $$C0$$−$$13C1+15C2$$⋯ upto $$(n+1)term$$ equal

Correct option is 2∫01 1−x2ndx

Questions

If $C_{r} =^{n} C_{r},$ then $C_{0} - \frac{1}{3} C_{1} + \frac{1}{5} C_{2} \dots upto (n + 1)$ term equal

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∫01 x(1−x)ndx

∫01 1−x2ndx

1+∫01 x(1+x)ndx

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detailed solution

Correct option is B

C0−13C1+15C2−⋯=∫01 C0−C1x2+C2x4−⋯dx=∫01 1−x2ndx

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If Cr=nCr,then C0−13C1+15C2⋯ upto (n+1)term equal

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If $C_{r} =^{n} C_{r},$ then $C_{0} - \frac{1}{3} C_{1} + \frac{1}{5} C_{2} \dots upto (n + 1)$ term equal