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If $C_{r} =^{n} C_{r},$ then the value of $(1 + \frac{C_{1}}{C_{0}}) (1 + \frac{C_{2}}{C_{1}}) \dots (1 + \frac{C_{n}}{C_{n - 1}})$

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(n+1)!2n

(n+1)nn!

2n−1n!

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detailed solution

Correct option is B

From the previous question, we have1+CrCr−1=n+1r∴1+C1C01+C2C1⋯1+CnCn−1=(n+1)nn!

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If Cr=nCr, then the value of 1+C1C01+C2C1⋯1+CnCn−1

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If $C_{r} =^{n} C_{r},$ then the value of $(1 + \frac{C_{1}}{C_{0}}) (1 + \frac{C_{2}}{C_{1}}) \dots (1 + \frac{C_{n}}{C_{n - 1}})$