If Cr stands for Cr n, then the sum of first ( n + 1 ) terms of the (n+1) terms of the series aC0−(a+d)C1+(a+2d)C2−(a+3d)C3+…, is
a2n
n a
0
none of these
We have,
aC0−(a+d)C1+(a+2d)C2−(a+3d)C3+…..........+(−1)n(a+nd)Cn
=∑r−0n (a+rd)(−1)rnCr=a∑r=0n (−1)rnCr−dn∑r=1n−1 n−1Cr−1(−1)r1=a×0−dn×0=0