If center of a regular hexagon is at the origin and one of the vertices on the Argand diagram is 1 + 2i, then its perimeter is
25
62
45
65
Let the vertices be z0, z1, ..., z5 w.r.t. center O at origin and z0=5.
Now ΔOA2A3 is equilateral
⇒ OA2=OA3=A2A3=5
Perimeter=65