If centre of a regular hexagon is at origin and one of the vertices on Argand diagram is 1+2i , then its perimeter is

Let the vertices be A1z1,A1z2,A1z3,A1z4,A1z5,A1z6  w.r.t centre O at origin and z1=1+2i. Then z1=5 Now Δ O A1A2  is equilateral ⇒ OA1=OA2=A1A2=5∴Perimeter = 65Hence option (4)