Q.
If the chord through the points whose eccentric angles are θ and ϕ on the ellipse x225+y29=1 passes through a focus, then the value of tan(θ/2) tan(ϕ/2) is
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a
1/9
b
-9
c
-1/9
d
9
answer is C.
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Detailed Solution
The equation of the line joining θ and ϕ isx5cosθ+ϕ2+y3sinθ+ϕ2=cosθ−ϕ2If it passes through the point (4,0), then45cosθ+ϕ2=cosθ−ϕ2 or 45=cos{(θ−ϕ)/2}cos{(θ+ϕ)/2} or 4+54−5=cos{(θ−ϕ)/2}+cos{(θ+ϕ)/2}cos{(θ−ϕ)/2}−cos{(θ+ϕ)/2} =2cos(θ/2)cos(ϕ/2)2sin(ϕ/2)sin(θ/2) or tanθ2tanϕ2=−19If it passes through the point (-4,0), then tanϕ2tanθ2=9
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