If a circle of constant radius 3k passes through the origin O and meets the coordinate axes at A and B, then the locus of the centroid of triangle OAB is

Let the centroid of triangle OAB be (p, q).Hence, points A and B are (3p,0) and (0,3q), respectively.But diameter of circle, AB = 6kHence, 9p2+9q2=6kTherefore, the locus of (p, q) is x2+y2=4k2.