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If a circle of constant radius 3k passes through the origin O and meets the coordinate axes at A and B, then the locus of the centroid of triangle OAB is 

a
x2+y2=(2k)2
b
x2+y2=(3k)2
c
x2+y2=(4k)2
d
x2+y2=(6k)2

detailed solution

Correct option is A

Let the centroid of triangle OAB be (p, q).Hence, points A and B are (3p,0) and (0,3q), respectively.But diameter of circle, AB = 6kHence, 9p2+9q2=6kTherefore, the locus of (p, q) is x2+y2=4k2.

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