Questions
If a circle has two of its diameters along the lines
and and has area then the equation of the circle
is
a
x2+y2−6x−4y+4=0
b
x2+y2−6x−4y−3=0
c
x2+y2−6x−4y−4=0
d
x2+y2−6x−4y+3=0
detailed solution
Correct option is A
Two diameters x+y=5 and x−y=1 intersect at(3, 2) which is the centre of the circle. Let r be the radius of thecircle. Then,Area =9π⇒πr2=9π⇒r=3.So, the equation of the circle is(x−3)2+(y−2)2=32 or, x2+y2−6x−4y+4=0Talk to our academic expert!
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