If a circle passes through (a, b)and cuts the circle x2+y2=4 orthogonally, then the locus of its centre is
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a
2ax−2by+a2+b2+4=0
b
2ax+2by−a2+b2+4=0
c
2ax+2by+a2+b2+4=0
d
2ax−2by−a2+b2+4=0
answer is B.
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Detailed Solution
Let the equation of the circle bex2+y2−2gx−2fy+c=0. As it passes through (a, b) a2+b2−2ga−2fb+c=0Since it intersects the circle x2+y2=4 orthogonally 2g×0+2f×0=c−4⇒c=4and the locus of (g,f), the centre is 2ax+2by−a2+b2+4=0