Questions
If a circle passes through and cuts the circle orthogonally then the equation of the locus of its centre, is
a
2x+4y-9=0
b
2x+4y+9=0
c
2x-4y+9=0
d
none of these
detailed solution
Correct option is A
Let the circle be x2+y2+2gx+2fy+c=0. This passes through (1, 2) and cuts the circle x2+y2=4 orthogonally.∴ 5+2g+4f+c=0 …(i) and, 0=c−4 ...(ii)Eliminating c from (i) and (ii), we get 2g+4f+9=0.Hence the locus of the centre (- g, - f ) is −2x−4y+9=0 or, 2x+4y−9=0Talk to our academic expert!
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