If the circle x2+y2=a2 intersects the hyperbola xy=c2 in four points Px1,y1,Qx2,y2,Rx3,y3,Sx4,y4 then
x1+x2+x3+x4=0
y1+y2+y3+y4=0
x1x2x3x4=c4
y1y2y3y4=c4
Solving xy=c2 and x2+y2=a2, we have
x2+c4x2=a2
⇒ x4−a2x2+c4 =0⇒ Σxi =0 and x1x2x3x4=c4
Similarly, if we eliminate y, then Σyi=0 and y1y2y3y4
=c4