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Q.

If the circles (x−α)2+(y−β)2=a2  : (x+β)2+(y+α)2=a2 touch each other then the point of contact is

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a

(α−β2,β+α2)

b

(α+β2,β−α2)

c

(α−β2,β−α2)

d

(2,2)

answer is C.

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Detailed Solution

C1=(α,β),C2=(−β,−α) ∵  radii are equal, point of contact is the mid point of C1C2 P=(α−β2,β−α2)
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