Download the app

Questions  

 If the coefficient of x7 in ax21bx11 equals the coefficient of x7 in ax1bx211 , then a and b satisfy the relation

a
a-b=1
b
a+b=1
c
a/b=1
d
ab=1

detailed solution

Correct option is D

Coefficient of x7 in ax2+1bx11 is 11C5a61b5 , Coefficient of x−7 in ax−1bx211 is 11C6a51b6  11C6a5⋅1b6=11C5⋅a6−1b5⇒ab= 11C6 11C5=66=1

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The coefficient of x4 in the expansion of 1+x+x2+x3n is


phone icon
whats app icon