Download the app

Binomial theorem for positive integral Index

Question

If coefficient of x3 and x4 in the expansion of 1+ax+bx2(12x)18  in powers of x are both zeros, then is (a, b) equal to

Moderate
Solution

S=1+ax+bx2(12x)18=1+ax+bx21+18C1(2x)+ 18C2(2x)2+18C3(2x)3+18C4(2x)4+. 

Coefficient of  in x3 the expansion of  18C3(2)3+a 18C2(2)2+18C1(2)b=0

Divide by  18C1(2) to obtain  

3043193a=0a=16

From (1),b=17×165443=2723



Talk to our academic expert!

+91

Are you a Sri Chaitanya student?



Similar Questions

lf the term independent of x in the expansion of 32x213x9is k, then 18k is equal to


phone icon
whats app icon