If the coefficients of (2r + 4)th and (r – 2)th terms in the expansion of (1+x)18 are equal, then value of r is
5
6
7
9
18C2r+3=18Cr−3⇒2r+3=r−3 or 18=(2r+3)+(r−3)⇒ r=−6 or r=6