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$If the coefficients of x^{9}, x^{10}, x^{11} in the expansion of (1 + x)^{n} are in arithmetic$ $progression then n^{2} - 41 n =$

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Correct option is C

Coefficients of x9,x10,x11 in (1+x)n are in A.P ⇒n2−41n+400=2⇒n2−4ln+398=0⇒n2−41n=−398 .

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If the coefficients of x9,x10,x11 in the expansion of (1+x)n are in arithmetic progression then n2−41n=

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Ready to Test Your Skills?

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$If the coefficients of x^{9}, x^{10}, x^{11} in the expansion of (1 + x)^{n} are in arithmetic$ $progression then n^{2} - 41 n =$