Q.

If ω is a complex cube root of unity then |11+ω1+ω21+ω1+ω211+ω211+ω|=

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a

–2

b

4

c

0

d

2

answer is B.

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Detailed Solution

|11+ω1+ω21+ω1+ω211+ω211+ω| =|1−ω2−ω−ω2−ω1−ω1−ω2|  =0+2+2=4
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