If the complex numbers iz, z and z+ iz represent the three vertices of a triangle, then the area of the triangle is
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a
1
b
12z2
c
12
d
12z+iz2
answer is B.
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Detailed Solution
Given z,iz and z+iz be the vertices of a triangle , thenlet z=x+iy∴ iz=-y+ix,z+iz=x-y+ix+yHence , required area =12xy1-yx1x-yx+y1 =12xy1-yx100-1R3→R3-R1+R2 =-12x2+y2 =12z2