If for complex numbers $$z1$$ and $$z2$$, arg $$z1$$−arg⁡$$z2=0$$ $$thenz1$$−$$z2$$ is equal to

Correct option is 3||z1|−|z2||

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If for complex numbers z₁ and z₂, arg $(z_{1}) - \arg (z_{2}) = 0$ then $|z_{1} - z_{2}|$ is equal to

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||z1|−|z2||

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detailed solution

Correct option is C

We have,z1−z22=z12+z22−2z1z2cos⁡θ1−θ2where θ1=arg⁡z1 and θ2=arg⁡z2 Given,arg⁡z1−z2=0⇒ z1−z22=z12+z22−2z1z2=z1−z22⇒ z1−z2=||z1|−|z2||

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If for complex numbers z1 and z2, arg z1−arg⁡z2=0 thenz1−z2 is equal to

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If for complex numbers z₁ and z₂, arg $(z_{1}) - \arg (z_{2}) = 0$ then $|z_{1} - z_{2}|$ is equal to