if the complex numbers z, z¯, z¯−2Rez¯ and z−2Rez represent the vertices of a square of the side 4 units in the argand plane then the modulus of z

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answer is C.

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Detailed Solution

suppose that z=x+iy⇒z¯=x−iyso the vertices will be x,y, x,−y, −x,−y, −x,yso sides of squares will be 2x,2yit gives x=y=2 , so that z=22

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