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Questions  

If the constant term in the binomial expansion of xkx210is 405, then |k| equal 

a
9
b
1
c
3
d
2

detailed solution

Correct option is C

Since, the general term in the expansion of binomialx−kx210 is Tr+1=10Crx10−r2(−k)rx−2r=10Cr(−k)rx10−5r2∵the Term is constant,So  r=2.∴     10C2(−k)2=405⇒    10×92k2=405⇒k2=9⇒|k|=3

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