First slide
Evaluation of definite integrals
Question

If for a continuous function f,

aaf(x)dx=K0a(f(x)+f(x))dx then the value of K is

Easy
Solution

aaf(x)dx=a0f(x)dx+0af(x)dx=a0f(x)dx+0af(x)dx=0a(f(x)+f(x))dx.

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