Q.

If for a continuous function f,∫−aa f(x)dx=K∫0a (f(x)+f(−x))dx then the value of K is

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a

1

b

1/2

c

2

d

a

answer is A.

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Detailed Solution

∫−aa f(x)dx=∫−a0 f(x)dx+∫0a f(x)dx=−∫a0 f(−x)dx+∫0a f(x)dx=∫0a (f(−x)+f(x))dx.
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