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Questions  

If acosAbsinA=c, then asinA+bcosA is equal to

a
a2+b2−c2
b
b2+c2−a2
c
c2+a2−b2
d
a2+b2+c2

detailed solution

Correct option is A

Put asin⁡A+bcos⁡A=x, then c2+x2=(acos⁡A−bsin⁡A)2+(asin⁡A+bcos⁡A)2=a2+b2⇒ x=a2+b2−c2

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