If acosA−bsinA=c, then asinA+bcosA is equal to
a2+b2−c2
b2+c2−a2
c2+a2−b2
a2+b2+c2
Put asinA+bcosA=x, then
c2+x2=(acosA−bsinA)2+(asinA+bcosA)2
=a2+b2⇒ x=a2+b2−c2