If cos(A−B)=35 and tan AtanB=2 then
cosA cosB=15
sinA sinB=−25
cosA cosB=-15
sinA sinB=−15
cos(A−B)=35
or 5cosAcosB+5sinAsinB=3 ------------(1)
From the second relation , we get
sinAsinB=2cosAcosB -----2⇒cosAcosB=15 and sinAsinB=25