If cos(θ−α),cosθ,cos(θ+α) are in H.P., then cosθsec(α/2)is equal to
-1
±2
±3
We are given that
cosθ=2cos(θ−α)cos(θ+α)cos(θ−α)+cos(θ+α)⇒ cosθ=2cos2θ−sin2α2cosθcosα
⇒ cos2θcosα=cos2θ−sin2α⇒ cos2θ=sin2α1−cosα⇒ cosθ=4sin2α2cos2α22sin2α2⇒ cos2θsec2α2=2⇒cosθsecα2=±2