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Questions  

If cosA+cosB+cosC=0 then cos3A+cos3B+cos3C is equal to

a
cos⁡Acos⁡Bcos⁡C
b
12cos⁡Acos⁡Bcos⁡C
c
0
d
8cos3⁡Acos3⁡Bcos3⁡C

detailed solution

Correct option is B

We have,cos⁡A+cos⁡B+cos⁡C=0cos3⁡A+cos3⁡B+cos3⁡C=3cos⁡Acos⁡Bcos⁡Ccos⁡3A+3cos⁡A4+cos⁡3B+3cos⁡B4+cos⁡3C+3cos⁡C4⇒ cos⁡3A+cos⁡3B+cos⁡3C=12cos⁡Acos⁡Bcos⁡C

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