First slide
Multiple and sub- multiple Angles
Question

If cosA+cosB+cosC=0 then cos3A+cos3B+cos3C is equal to

Moderate
Solution

We have,

cosA+cosB+cosC=0cos3A+cos3B+cos3C=3cosAcosBcosC

cos3A+3cosA4+cos3B+3cosB4+cos3C+3cosC4

 cos3A+cos3B+cos3C=12cosAcosBcosC

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