First slide
Trigonometric transformations
Question

If cosA+cosB+cosC=0 then cos3A+cos3B+cos3C=λcosAcosBcosC then λ=

Moderate
Solution

cosA+cosB+cosC=0

cos3A+cos3B+cos3C

=3cosAcosBcosC and cos3A+cos3B+cos3C

=4(cos3A+cos3B+cos3C)3(cosA+cosB+cosC)

=4(3cosAcosBcosC)3(0)

=12cosacosBcosC

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App