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Q.

If cosα+cosβ+cosγ=sinα+sinβ+sinγ=0  then

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a

cos2α+cos2β+cos2γ=0

b

sin2α+sin2β+sin2γ=0

c

cos(α+β)+cos(β+γ)+cos(γ+α)=0

d

sin(α+β)+sin(β+γ)+sin(γ+α)=0

answer is A.

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Detailed Solution

Let a=cisα,b=cisβ,c=cisγ , then⇒ a+b+c=0 ,1a+1b+1c=0⇒cis2α+cis2β+cis2γ=0  and  cis(α+β)+cis(β+γ)+cis(γ+α)=0a2+b2+c2=0  and  ab+bc+ca=0
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If cosα+cosβ+cosγ=sinα+sinβ+sinγ=0  then