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Q.

If cosα+cosβ=0=sinα+sinβ,  then cos2α+cos2β is equal to

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a

−2sin(α+β)

b

−2cos(α+β)

c

2sin(α+β)

d

2cos(α+β)

answer is B.

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Detailed Solution

(cosα+cosβ)2−(sinα+sinβ)2=0
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