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Q.

If cosα+cosβ=sinα+sinβ,then cos2α+cos2β=

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a

−2sinα+β

b

−2cosα+β

c

2sinα+β

d

2cosα+β

answer is B.

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Detailed Solution

cosα+cosβ=sinα+sinβon  Squaring, cos2α+cos2β+2cosαcosβ= sin2α+sin2β+2sinαsinβ⇒cos2α-sin2α+cos2β-sin2β=-2cosαcosβ-sinαsinβ⇒cos2α+cos2β=-2cosα+β
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