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Questions  

If cosα+cosβ=sinα+sinβ,then cos2α+cos2β=

a
−2sinα+β
b
−2cosα+β
c
2sinα+β
d
2cosα+β

detailed solution

Correct option is B

cosα+cosβ=sinα+sinβon  Squaring, cos2α+cos2β+2cosαcosβ= sin2α+sin2β+2sinαsinβ⇒cos2α-sin2α+cos2β-sin2β=-2cosαcosβ-sinαsinβ⇒cos2α+cos2β=-2cosα+β

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