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If $6 \cos 2 θ + 2 \cos^{2} (θ / 2) + 2 \sin^{2} θ = 0$ where $- π < 0 < π$ , then $θ$ is equal to

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π/3

π/3,cos−13/5

cos−13/5

π/3,π−cos−13/5

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detailed solution

Correct option is D

The given equation can be written as62cos2θ−1+1+cosθ+21−cos2θ=0⇒10cos2θ+cosθ−3=0⇒5cosθ+32cosθ−1=0⇒cosθ=12 or ⇒cosθ=-35⇒θ=π3 or θ=π−cos−135 as −π<θ<π⇒θ=π3,π−cos−135

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If 6cos2θ+2cos2θ/2+2sin2θ=0 where −π<0<π , then θ is equal to

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If $6 \cos 2 θ + 2 \cos^{2} (θ / 2) + 2 \sin^{2} θ = 0$ where $- π < 0 < π$ , then $θ$ is equal to