If 6cos2θ+2cos2θ/2+2sin2θ=0 where −π<0<π , then θ is equal to
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
π/3
b
π/3,cos−13/5
c
cos−13/5
d
π/3,π−cos−13/5
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The given equation can be written as62cos2θ−1+1+cosθ+21−cos2θ=0⇒10cos2θ+cosθ−3=0⇒5cosθ+32cosθ−1=0⇒cosθ=12 or ⇒cosθ=-35⇒θ=π3 or θ=π−cos−135 as −π<θ<π⇒θ=π3,π−cos−135