If cosβ is the geometric mean between sinα and cosα where 0<α,β<π/2 then cos2β is equal to
−2sin2π4−α
−2cos2π4+α
2sin2π4+α
2cos2π4−α
2sinαcosα=2cos2βsin2α=1+cos2β∴ cos2β=−(1−sin2α) =−1−cosπ2−2α =−2sin2π4−α =−2cos2π4+α