Q.
If (acosθi,asinθi),i=1,2,3 represent the vertices of an equilateral triangle inscribed in a circle , then
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a
cosθ1+cosθ2+cosθ3=0
b
sinθ1+sinθ2+sinθ3=0
c
tanθ1+tanθ2+tanθ3=0
d
cos(θ1−θ2)=−12
answer is Ü.
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Detailed Solution
Given points lie in the circle x2+y2=a2 since the points are vertices of an equilateral triangle∴ Circumcentre(0) and centroid of triangle are same a3(cosθ1+cosθ2+cosθ3)=0 and a3(sinθ1+sinθ2+sinθ3)=0 ⇒cosθ1+cosθ2+cosθ3=0 and sinθ1+sinθ2+sinθ3=0and cosθ1+cosθ22 +sinθ1+sinθ22= -cosθ32+-sinθ32 =1⇒1+1+2cosθ1-θ2=1 ⇒cosθ1-θ2=-12
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