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Questions  

If ω=cosπn+i sinπn, then value of 1+ω+ω2+....+ωn-1 is 

a
1+i cotπ2n
b
1+i tanπn
c
1+i
d
none of these

detailed solution

Correct option is A

We have       1+ω+ω2+…+ωn−1=1−ωn1−ω=21−ωas ωn=cos⁡nπn+isin⁡nπn=cos⁡π+isin⁡π=−1Now,        21−ω=2(1−ω¯)(1−ω)(1−ω¯)=2(1−ω¯)1−(ω+ω¯)+ωω¯=2(1−ω¯)2−2Re⁡(ω)     ∵ωω¯=|ω|2=1=1−Re⁡(ω)+iIm⁡(ω)1−Re⁡(ω)=1+iIm⁡(ω)1−Re⁡(ω)=1+isin⁡πn1−cos⁡πn=1+i2sin⁡π2ncos⁡π2n2sin2⁡π2n=1+icot⁡(π/2n)

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