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If $\begin{array}{l} A = [\begin{array}{rr} \cos θ & \sin θ \\ - \sin θ & \cos θ \end{array}], \end{array}$ then $A^{2} = 1$ is true for

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θ=0

θ=π4

θ=π2

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Correct option is A

We have, A2=cos⁡2θ sin⁡2θ−sin⁡2θ cos⁡2θ A2=I⇒cos⁡2θ=1 and sin⁡2θ=0⇒θ=0

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If A=cos⁡θsin⁡θ−sin⁡θcos⁡θ, then A2=1 is true for

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If $\begin{array}{l} A = [\begin{array}{rr} \cos θ & \sin θ \\ - \sin θ & \cos θ \end{array}], \end{array}$ then $A^{2} = 1$ is true for