If cos2π7−sin2π7sin2π7cos2π7k=1001, then the least positive integral value of k is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
answer is 7.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
we know that cosθ−sinθsinθcosθn=cosnθ−sinnθsinnθcosnθ∴cos2π7−sin2π7sin2π7cos2π7k=cos2kπ7−sin2kπ7sin2kπ7cos2kπ7=1001, if k=7m, where m∈NHence, the least value of k is 7.