First slide
Operations of matrix
Question

If cos2π7sin2π7sin2π7cos2π7k=1001, then the least positive integral value of k is

Moderate
Solution

we know that cosθsinθsinθcosθn=cossinsincos

cos2π7sin2π7sin2π7cos2π7k=cos27sin27sin27cos27=1001,     if k=7m, where mN

Hence, the least value of k is 7.

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