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 If A=cosαsinα0sinαcosα0001, then (AdjA)1=

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a
cosα−sinα0sinαcosα0001
b
−cosα−sinα0sinα−cosα0001
c
−cosαsinα0sinα−cosα0001
d
1000cosα−sinα0sinαcosα

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detailed solution

Correct option is A

det  A=cosαcosα−0+sinαsinα−0=cos2α+sin2α=1∴A−1=Adj  A⇒Adj  A−1=A−1−1=A


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