Q.
If A=cosα−sinα0sinαcosα0001, then (AdjA)−1=
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a
cosα−sinα0sinαcosα0001
b
−cosα−sinα0sinα−cosα0001
c
−cosαsinα0sinα−cosα0001
d
1000cosα−sinα0sinαcosα
answer is A.
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Detailed Solution
det A=cosαcosα−0+sinαsinα−0=cos2α+sin2α=1∴A−1=Adj A⇒Adj A−1=A−1−1=A
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