If A(cosα,sinα),B(sinα,−cosα),C(1,2) are the varties △ABC then as a varies the locus of its centroid, is
x2+y2−2x−4y+1=0
3x2+y2−2x−4y+1=0
x2+y2−2x−4y+3=0
none of these
let (h, k) be the centroid of the triangle having
A(cosα,sinα),B(sinα,−cosα) and C(1,2) Then h=cosα+sinα+13 and k=sinα−cosα+23
⇒ 3h−1=cosα+sinα
⇒ 9h2+k2−6h−12k+3=0⇒ 3h2+k2−2h−4k+1=0
Hence, the locus of (h,k) is 3x2+y2−2x−4y+1=0