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If A(cosα,sinα),B(sinα,cosα),C(1,2) are the varties ABC then as a varies the locus of its centroid, is

a
x2+y2−2x−4y+1=0
b
3x2+y2−2x−4y+1=0
c
x2+y2−2x−4y+3=0
d
none of these

detailed solution

Correct option is B

let (h, k) be the centroid of the triangle havingA(cos⁡α,sin⁡α),B(sin⁡α,−cos⁡α) and C(1,2) Then h=cos⁡α+sin⁡α+13 and k=sin⁡α−cos⁡α+23 ⇒ 3h−1=cos⁡α+sin⁡α⇒ 9h2+k2−6h−12k+3=0⇒ 3h2+k2−2h−4k+1=0Hence, the locus of (h,k) is 3x2+y2−2x−4y+1=0

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