If A=1+cos2θsin2θ4cos6θcos2θ1+sin2θ4cos6θcos2θsin2θ1+4cos6θ is a singular matrix and 3θ∈(0,π) then θ=
π9
π18
π6
π12
|A|=0⇒2+4cos6θ=0⇒cos6θ=−12 ⇒6θ=2π3⇒θ=π9