If cosθsinθ+sin2θ+sin2α≤k then the value of k is
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a
1+cos2α
b
1+sin2α
c
2+sin2α
d
2+cos2α
answer is B.
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Detailed Solution
Let u=cosθsinθ+sin2θ+sin2αor (u−sinθcosθ)2=cos2θsin2θ+sin2αor u2tan2θ−2utanθ+u2−sin2α=0Since tan θ is real, we have 4u2−4u2u2−sin2α≥0 or u2≤1+sin2α or |u|≤1+sin2α