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Q.

If cos⁡θsin⁡θ+sin2⁡θ+sin2⁡α≤k then the value of k is

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a

1+cos2⁡α

b

1+sin2⁡α

c

2+sin2⁡α

d

2+cos2⁡α

answer is B.

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Detailed Solution

Let u=cos⁡θsin⁡θ+sin2⁡θ+sin2⁡αor (u−sin⁡θcos⁡θ)2=cos2⁡θsin2⁡θ+sin2⁡αor  u2tan2⁡θ−2utan⁡θ+u2−sin2⁡α=0Since tan θ is real, we have     4u2−4u2u2−sin2⁡α≥0 or      u2≤1+sin2⁡α or  |u|≤1+sin2⁡α
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