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Questions  

If Aα= cosα     sinαsinα    cosα then thatAα.Aβ=

a
Aα−β
b
Aβ−α
c
Aα+β
d

detailed solution

Correct option is C

we have,Aα.Aβ= cosα     sinα−sinα    cosα cosβ     sinβ−sinβ    cosβ= cosαcosβ−sinαsinβ    sinαcosβ+cosαsinβ−sinαcosβ−cosαsinβ   cosαcosβ−sinαsinβ= cos(α+β)    sin(α+β) −sin(α+β)   cos(α+β)=Aα+β

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