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If $\cos θ = 1 - 2 t^{2}$ , $0^{\circ} < t < 180^{\circ}$ and $\cos 50^{\circ} = t$ then the value of $θ$ is

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Correct option is A

cosθ=1−2t2=1−2cos2500=−cos1000 =cos(1800−1000)=cos800∴θ=800

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If cosθ=1−2t2, 0∘<t<180∘ and cos50∘=t then the value of θ is

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If $\cos θ = 1 - 2 t^{2}$ , $0^{\circ} < t < 180^{\circ}$ and $\cos 50^{\circ} = t$ then the value of $θ$ is