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Questions  

If cosA=3/4, then the value of 16cos2(A/2)32sin(A/2)sin(5A/2) is

a
-4
b
-3
c
3
d
4

detailed solution

Correct option is C

The given expression is equal to8(1+cos⁡A)−16(cos⁡2A−cos⁡3A)=8(1+cos⁡A)−162cos2⁡A−1−cos⁡A4cos2⁡A−3=81+34−162×916−1−344×916−3=14−(18−16−27+36)=3.

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