First slide
Multiple and sub- multiple Angles
Question

If cosA=3/4, then the value of 16cos2(A/2)32sin(A/2)sin(5A/2) is

Moderate
Solution

The given expression is equal to

8(1+cosA)16(cos2Acos3A)=8(1+cosA)162cos2A1cosA4cos2A3=81+34162×9161344×9163=14(181627+36)=3.

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