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Questions  

If cosA=34, then the value of sinA2sin5A2, is

a
132
b
118
c
1132
d
1116

detailed solution

Correct option is C

We have,sin⁡A2sin⁡5A2=122sin⁡A2sin⁡5A2=12(cos⁡2A−cos⁡3A)=122cos2⁡A−1−4cos3⁡A+3cos⁡A=122×916−1−4×2764+3×34=1132

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