First slide
Properties of ITF
Question

If cos1xcos1y2=α then 4x24xycosα+y2 is equal to 

Moderate
Solution

We have,

cos1xcos1y2=α cos1xy2+1x21y24=α xy2+1x21y24=cosα cosαxy22=1x21y24 cos2α+x2y24xycosα=1x2y24+x2y24 x2+y24xycosα=sin2α 4x24xycosα+y2=4sin2α

 

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App