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Questions  

If cos1xcos1y2=α then 4x24xycosα+y2 is equal to 

a
−4sin2⁡α
b
4sin2⁡α
c
4
d
2sin⁡2α

detailed solution

Correct option is B

We have,cos−1⁡x−cos−1⁡y2=α⇒ cos−1⁡xy2+1−x21−y24=α⇒ xy2+1−x21−y24=cos⁡α⇒ cos⁡α−xy22=1−x21−y24⇒ cos2⁡α+x2y24−xycos⁡α=1−x2−y24+x2y24⇒ x2+y24−xycos⁡α=sin2⁡α⇒ 4x2−4xycos⁡α+y2=4sin2⁡α

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