If cos−1x+cos−1y=π2 and tan−1x−tan−1y=0, then x2 + xy + y2, is equal to
0
12
32
18
∵tan−1x−tan−1y=0⇒x=y Also, cos−1x+cos−1y=π2 ⇒2cos−1x=π2⇒cos−1x=π4⇒x=12⇒x2=12 Hence, x2+xy+y2=3x2=32