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Questions  

If 2cosx+2cos3x=cosy,2sinx+2sin3x=siny then the value of cos2x of 

a
– 7/8
b
1/8
c
– 1/8
d
7/8

detailed solution

Correct option is A

cos⁡y=2×2cos ⁡2xcos ⁡xsin⁡y=2×2sin⁡2xcos⁡x ⇒1=cos2⁡y+sin2⁡y=16cos2⁡xSo cos⁡2x=2cos2⁡x−1=−7/8

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