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Multiple and sub- multiple Angles

Question

If cos4x=a0+a1cos2x+a2cos4x s true for all values of xR then the value of 5a0+a1+a2 is

Moderate
Solution

cos4x=2cos22x1=22cos2x121=24cos4x+14cos2x1=8cos4x8cos2x+1 a0=1,a1=8,a2=8 5a0+a1+a2=5



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