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Properties of ITF

Question

If  cos1x+cos12x+cos13x=πand  ax3+bx2+cx=0 satisfies the equation  then the value of bac100 is 

Moderate
Solution

cos1x+cos12x+cos13x=π cos12x+cos13x=π-cos1x=cos-1-x 6x2-1-4x21-9x2=-x 6x2+x=1-4x21-9x2 36x4+12x3+x2=1-13x2+36x4 12x3+14x2-1=0

a=12,b=14,c=-1 b-a-c100=3100=0.03



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